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Tanya Maniktala

Born
Jul 7, 1997age 29
height
5'6" (or 167 cm)
body type
Average
nationality
Indian

Biography

About Tanya Maniktala

Edited by the community

Tanya Maniktala stands 5'6" tall with black hair, brown eyes, and an average build. She was born on Monday 7th of July 1997 in New Delhi, India, and holds Indian nationality. As an actress, she has made a mark in the entertainment industry.

Her measurements are 33–26–34, with a bra cup size of 32B, and she has natural breasts. Tanya is of Asian ethnicity and identifies as straight. With 879k Instagram followers, she enjoys a significant online presence. Her talent and dedication have earned her recognition, and she continues to explore diverse roles.

Record

Profile details

Personal

Birthplace
New Delhi, New Delhi, India
Ethnicity
Asian
Sexuality
Straight

Body

Hair Color
Black
Eye Color
Brown
Weight
115 lbs (or 52 kg)
Measurements
33–26–34 (B–W–H) · WHR 0.76
Bra/Cup Size
32B show conversions - UK: 32B, EU: 70B, AU: 10B, JP: 70B

Extra

Instagram Followers
879k (as of July 2026)

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Frequently asked

What is Tanya Maniktala's body type and measurements?

Tanya has an average body type with measurements of 33–26–34 (B–W–H), and a bra cup size of 32B.

How tall is Tanya Maniktala and what is her weight?

Tanya is 5'6" (167 cm) tall and weighs 115 lbs (52 kg).

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