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Aline Segatti

Born
Jun 6, 1981age 45
height
5'10" (or 177 cm)
body type
Average
nationality
American

Biography

About Aline Segatti

Edited by the community

Aline Segatti was born on Saturday, the 6th of June 1981, in Atlanta, Georgia, United States. She is American, with Latin ethnicity, and works as a Glamour Model. At 45 years old, she stands 5'10" tall and has a natural 34E bra cup size, with measurements of 34–28–38. Her black hair and brown eyes complement her average build, weighing 143 lbs. Segatti's real, natural bust is a notable feature of her figure. Her career in glamour modeling has showcased her striking presence. With a height of 5'10", she stands out in the industry. Her measurements, including a waist-to-hip ratio of 0.74, contribute to her distinctive silhouette. Despite being in her mid-40s, she continues to work as a model, maintaining a classic yet understated appeal. Segatti's American roots and Latin background add depth to her public persona, though she keeps much of her personal life out of the spotlight.

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Profile details

Personal

Birthplace
Atlanta, Georgia, United States
Ethnicity
Latin

Body

Hair Color
Black
Eye Color
Brown
Weight
143 lbs (or 65 kg)
Measurements
34–28–38 (B–W–H) · WHR 0.74
Bra/Cup Size
34E show conversions - UK: 34E, EU: 75E, AU: 12E, JP: 75E

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Frequently asked

What is her height and weight combination?

She is 5'10" tall and weighs 143 lbs, giving her an average body type.

What does her physique indicate about her figure?

With measurements of 34–28–38 and a natural 34E cup, her figure has an hourglass-like shape, as reflected in her waist-to-hip ratio of 0.74.

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